IRWIN, IOWA

'Irwin' is a city in Shelby County, Iowa, United States, along the West Nishnabotna River. The population was 372 at the 2000 census.

Contents

Geography

Demographics

External links

Geography

Irwin is located at (41.790449, -95.207341).
According to the United States Census Bureau, the city has a total area of 1.6 km² (0.6 mi²), all land.

Demographics

As of the census of 2000, there were 372 people, 168 households, and 110 families residing in the city. The population density was 239.4/km² (624.4/mi²). There were 180 housing units at an average density of 115.8/km² (302.1/mi²). The racial makeup of the city was 98.92% White, 0.27% African American, 0.27% Native American, and 0.54% from two or more races. Hispanic or Latino of any race were 2.15% of the population.
There were 168 households out of which 25.0% had children under the age of 18 living with them, 57.7% were married couples living together, 6.0% had a female householder with no husband present, and 34.5% were non-families. 32.1% of all households were made up of individuals and 19.0% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.76.
In the city the population was spread out with 21.2% under the age of 18, 6.2% from 18 to 24, 22.6% from 25 to 44, 24.2% from 45 to 64, and 25.8% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 90.8 males. For every 100 females age 18 and over, there were 91.5 males.
The median income for a household in the city was $30,417, and the median income for a family was $40,000. Males had a median income of $28,000 versus $18,393 for females. The per capita income for the city was $15,429. About 7.4% of families and 9.8% of the population were below the poverty line, including 9.8% of those under age 18 and 13.5% of those age 65 or over.

External links