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EspañolRANDOLPH, UTAH
'Randolph' is a city in Rich County, Utah, in the United States. As of the 2000 census, the city population was 483. It is the county seat of Rich County. Randolph had the highest percentage of people of any city in the country vote for George W. Bush in the 2004 election, at 95.6%.[1]
Randolph is located at (41.664397, -111.183461).
According to the United States Census Bureau, the city has a total area of 2.7 km² (1.0 mi²), all land.
As of the census of 2000, there were 483 people, 150 households, and 118 families residing in the city. The population density was 179.3/km² (466.1/mi²). There were 190 housing units at an average density of 70.5/km² (183.4/mi²). The racial makeup of the city was 99.38% White, 0.21% Asian, and 0.41% from two or more races. Hispanic or Latino of any race were 1.86% of the population.
There were 150 households out of which 49.3% had children under the age of 18 living with them, 73.3% were married couples living together, 2.7% had a female householder with no husband present, and 20.7% were non-families. 18.7% of all households were made up of individuals and 7.3% had someone living alone who was 65 years of age or older. The average household size was 3.21 and the average family size was 3.74.
In the city the population was spread out with 38.5% under the age of 18, 7.2% from 18 to 24, 26.3% from 25 to 44, 16.8% from 45 to 64, and 11.2% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 101.3 males. For every 100 females age 18 and over, there were 102.0 males.
The median income for a household in the city was $34,792, and the median income for a family was $42,917. Males had a median income of $35,625 versus $20,833 for females. The per capita income for the city was $13,477. About 9.5% of families and 14.0% of the population were below the poverty line, including 17.6% of those under age 18 and 3.5% of those age 65 or over.
As of January 2007, MapQuest appears to have better aerial images for this area than the above sites.
| Contents |
| Geography |
| Demographics |
| External links |
Geography
Location of Randolph, Utah
Randolph is located at (41.664397, -111.183461).
According to the United States Census Bureau, the city has a total area of 2.7 km² (1.0 mi²), all land.
Demographics
As of the census of 2000, there were 483 people, 150 households, and 118 families residing in the city. The population density was 179.3/km² (466.1/mi²). There were 190 housing units at an average density of 70.5/km² (183.4/mi²). The racial makeup of the city was 99.38% White, 0.21% Asian, and 0.41% from two or more races. Hispanic or Latino of any race were 1.86% of the population.
There were 150 households out of which 49.3% had children under the age of 18 living with them, 73.3% were married couples living together, 2.7% had a female householder with no husband present, and 20.7% were non-families. 18.7% of all households were made up of individuals and 7.3% had someone living alone who was 65 years of age or older. The average household size was 3.21 and the average family size was 3.74.
In the city the population was spread out with 38.5% under the age of 18, 7.2% from 18 to 24, 26.3% from 25 to 44, 16.8% from 45 to 64, and 11.2% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 101.3 males. For every 100 females age 18 and over, there were 102.0 males.
The median income for a household in the city was $34,792, and the median income for a family was $42,917. Males had a median income of $35,625 versus $20,833 for females. The per capita income for the city was $13,477. About 9.5% of families and 14.0% of the population were below the poverty line, including 17.6% of those under age 18 and 3.5% of those age 65 or over.
External links
As of January 2007, MapQuest appears to have better aerial images for this area than the above sites.
This article provided by Wikipedia. To edit the contents of this article, click here for original source.
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