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 | The truth behind the moon landings part 2 english UK amount of heat in the air isn't enough to burn you quickly, whereas the amount in the grill or pan will be. Also the solid conducts heat a lot faster than the air, but a vacuum is the poorest conductor of all. So it may be plus 200 degrees in the lunar sunlight and minus 200 in the shade, but in a vacuum there is no heat. The only way to cool off in a vacuum is by radiating away heat - there's no surrounding material to conduct heat away. It doesn't take much insulation to protect an ... |
 | Acer Aspire 5720-4126 Refurbished Laptop Computer all, processor is a pentium dual core. It's a T2330, that's a 1.6 GHz. It's got to gigabytes of DDR2 memory on there. It's got a 160 gig hard drive, the DVD-RW that I did mention before is dual layer and will do all the other formats so Rs, plus Rs, minus Rs, RWs, RAMs, ROMs, it will do pretty much all of them. You do get this nice webcam up here which they call crystal eye. It actually produces a really, really good image. I couldn't believe how good it looked for only being a 1.3 mega pixel ... |
 | Lec 4 | MIT 8.02 Electricity and Magnetism, Spring 2002 potential is everywhere positive and you expect them to be spherical again. If you look here you're very far away from the plus four and the minus one, indeed this has already the shape of a sphere. So that's clear that the plus four and the minus one far away behave like a plus three. If you're very close to the plus four, you get nice spheres around the plus four, positive potential, if you're very close to the minus one, notice that the blue surfaces are almost nice spheres, but now they' ... |
 | Lec 27 | MIT 8.02 Electricity and Magnetism, Spring 2002 function, so d phi E/dT. L and E0 can come out, that's no problem, they are constants. I tae the time derivative of cosine (KZ - omega T), then minus omega pops out, and the cosine becomes a minus sine. So I get minus the sine of (KZ - omega T). And I have to do an integral -- here is my dZ, 0 to lambda / 4. This minus sign eats up this minus sign. I have to do the integral, but I do that at T = 0. In other words, this thing goes away, because T = 0. So I'm getting close. So I'm going ... |
 | Lec 10 | MIT 8.02 Electricity and Magnetism, Spring 2002 direction. Through the resistance, the current flows in this direction. In what direction is the electric field? The electric field always runs from plus to minus potential. So right here, in this resistor, the electric field is in this direction, from plus to minus. But inside the supply it must also go from plus to minus. And so inside the supply, the electric field is in the direction that opposes the current. So some kind of a pump mechanism must force the current to go inside the ... |
 | Lec 15 | 8.01 Physics I: Classical Mechanics, Fall 1999 of these vectors. So now I have that 4m times the x component of the center of mass equals this mass times the x component of its position vector, which is zero, plus this mass, which is 2m times the x position, which is l-- so plus 2m times l-- plus this mass times the x component of this mass, which is one-half l. So that gives me plus one-half m times l. My m goes and so I get that x center of mass equals 2½ divided by four. That is five-eighths l. So we were not too far off where ... |
 | Lec 12 | MIT 3.091 Introduction to Solid State Chemistry we have a strong covalent bond within the molecule and we know the shape of the molecule. It is linear. But how does this hydrogen chloride bond to another hydrogen chloride? Well, we can see that this is delta minus, this is delta plus, and so this delta minus end is attracted to the delta plus end of an adjacent molecule and so on and so on. So this is a dipole-dipole interaction that, when the temperature is low enough, the thermal energy will not disrupt the bonds that are forming by ... |
 | Lec 4 | 8.01 Physics I: Classical Mechanics, Fall 1999 acceleration and the one-dimensional equations in the y direction where there is acceleration. In order to use these equations we need all these constants-- x zero, v zero x and v zero y. We have seen those last time. I choose for x zero... I choose zero arbitrarily. Also for y zero. The velocity in the x direction will never change. This v zero x will always remain v zero cosine alpha. The velocity in the y direction, however, in the beginning at t equals zero is v zero sine alpha. And ... |
 | Lec 23 | 8.01 Physics I: Classical Mechanics, Fall 1999 can give in hertz. I could give you a specific example. I, for instance, can take a period T of two times ten to the minus 15 seconds. That would give me a wavelength of about six times ten to the minus seven meters-- six times ten to the minus seven meters-- and that you would experience as red light. If I make the period shorter-- say, 1.3 times ten to the minus 15 seconds-- I get a shorter wavelength. I get four times ten to the minus seven meters, and you would experience that as blue ... |
 | Lec 12 | 8.01 Physics I: Classical Mechanics, Fall 1999 speed, and so you see when you are at lower speeds, when you work here, again, you see that you fall into... exclusively in domain one, and you see that the terminal speed is proportional to r square. This slope here is plus two in this diagram and this slope here is plus one-half. Our ball bearings are all here, and so we are exclusively operating in regime one where the viscous term dominates. Now you could say, "Well, what is the meaning of this critical speed here if they never reach ... |
